Ricci curvature
Category:Riemannian geometry
In
differential geometry,
Ricci curvature is 2-valent
tensor, obtained as a
trace of the full
curvature tensor. \nIt can be thought of as a
Laplacian of the
Riemannian metric tensor in the case of Riemannian manifolds.
It is usually denoted by
Ric. \nGiven an orthonormal basis \n in the tangent space at
p we have
-
where
R denotes the
curvature tensor, the result does not depend on the choice of orthonormal basis.
Ricci curvature can be also explained in terms of the
sectional curvature in the following way: for a unit vector
v,
is sum of the sectional curvatures of all the planes spanned by the vector
v and a vector from an orthonormal frame containing
v (there are
n-1 such planes). Here
<.,.> is metric scalar product.
One can think of Ricci curvature on a
Riemannian manifold, as being an operator on the tangent space. \nIf this operator is just multiplication by a constant, then we have an
Einstein manifold. \nThe Ricci curvature is proportional to the metric tensor in this case.
In dimensions 2 and 3 Ricci curvature describes completely the
curvature tensor, but in higher dimensions Ricci curvature contains less information. For instance, Einstein manifolds do not have to have constant curvature in dimensions 4 and up.
Applications of the Ricci curvature tensor
The Ricci curvature can be used to define Chern classes of a manifold, which are topological invariants (so independent of the choice of metric).
Ricci curvature is also used in Ricci flow, where a metric is deformed in the direction of the Ricci curvature. On surfaces, the flow produces a metric of constant Gauss curvature and the uniformization theorem for surfaces follows. \nIn dimension 3, it was recently used to give a complete classification of compact 3-manifolds.
Ricci curvature plays an important role in general relativity, where it is the key term in the Einstein field equations.
Global geometry/topology and Ricci curvature
Here is a short list of most basic results on manifolds with positive Ricci curvature.
- Mayers theorem states that if Ricci curvature is bounded from below on a complete Riemannian manifold by , then its diameter , and manifold has to have a finite fundamental group. If the diameter is equal to , then the manifold is isometric to a sphere of a constant curvature k.\n#Bishop-Gromov inequality states that if Ricci curvature of a complete m-dimensional Riemannian manifold is ≥0 then the volume of a ball is smaller or equal to the volume of a ball of the same radius in Eulidean m-space. More over if denotes the volume of the ball with center p and radius in the manifold and denotes the volume of the ball of radius R in Euclidean m-space then function is nonincreasing. (The last inequality can be generalized to arbitrary curvature bound and is the key point in the proof of Gromov's compactness theorem.)\n#Splitting theorem states that if a complete Riemannian manifold with Ricc ≥ 0 has a straight line (i.e. a geodesic γ such that for all ) then it is isometric to a product space where is a Riemannian manifold.
All results above show that positive Ricci curvature does have some geometric meaning, on the contrary negative curvature is not that restrictive, in particular as it was shown by Joachim Lohkamp, any manifold admit a metric of negative curvature.
See also
